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Past exam of the mathematics course of the University of Cambridge / 2022 / iii / Paper 221 / 3 / i / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2022 iii Paper 221 3 i
2026-09-28  0 By others on same topic  0 Discussions Create my own version
The no unmeasured confounding assumption, or conditional exchangeability, is
(Y(0),Y(1))⊥A∣X.
(1)
Also assume consistency of potential outcomes, no interference in causal inference, positivity in causal inference, and finite expectations. For a∈{0,1}, the law of total expectation, exchangeability, and consistency give
E[Y(a)]​=E{E[Y(a)∣X]}=E{E[Y(a)∣A=a,X]}=E{E[Y∣A=a,X]}.​
(2)
Positivity ensures that the observed conditional means exist on the covariate support being averaged. Subtracting the two cases identifies the average treatment effect as
β1​=E{E[Y∣A=1,X]}−E{E[Y∣A=0,X]}.
(3)

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