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Past exam of the mathematics course of the University of Cambridge / 2022 / iii / Paper 317 / 1 / i / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2022 iii Paper 317 1 i
2026-09-28  0 By others on same topic  0 Discussions Create my own version
The stellar structure equations are
drdMr​​=4πr2ρ,drdP​=−r2GMr​ρ​,
(1)
drdLr​​=4πr2ρϵ,drdT​=−16πarad​cr2T33κρLr​​,
(2)
with
P=Pg​+Prad​,Pg​=μHρkB​T​,Prad​=3arad​T4​,κ=κ0​ρT−7/2.
(3)
The last relation is the Kramers opacity law. Uniform energy release per unit mass means ϵ is constant, so integration of the mass and luminosity equations gives Lr​=ϵMr​. At the surface,
ϵ=ML​=M−1L​.
(4)
Thus ϵ=MaLb has
a=−1,b=1​.
(5)

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