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Past exam of the mathematics course of the University of Cambridge / 2023 / ii / Paper 2 / 3I / b / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2023 ii Paper 2 3I b
Created 2026-09-24 Updated 2026-10-03  0 By others on same topic  0 Discussions Create my own version
The first m letters of the blocked source contain exactly the first mN letters of the original source, so
H(Y1​,…,Ym​)=H(X1​,…,XmN​).
(1)
If the original information rate is h, then
limm→∞​m1​H(Y1​,…,Ym​)=Nlimm→∞​mN1​H(X1​,…,XmN​)=Nh.
(2)
Thus fixed-length blocking multiplies information rate by N, exactly as recorded by information rate under fixed-length blocking.

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