No. Let , let be the one-dimensional subalgebra generated by the standard raising operator, and let be the irreducible defining representation. On restriction to , the element acts by a nonzero Nilpotent Jordan block. A direct sum of irreducible representations of the one-dimensional abelian Lie algebra would make diagonalizable, so this restriction is not completely reducible. The Complete reducibility of semisimple Lie algebra representations applies when the restricting algebra is semisimple, which is not.
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