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Past exam of the mathematics course of the University of Cambridge / 2023 / iii / Paper 216 / 3 / c / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2023 iii Paper 216 3 c
2026-09-28  0 By others on same topic  0 Discussions Create my own version
By the stationary distribution property, X1​ and X2​ have the same marginal distribution π. Expanding the square gives
21​E[(f(X2​)−f(X1​))2]​=21​(2⟨f,f⟩π​−2E[f(X1​)f(X2​)])=⟨f,f⟩π​−⟨f,Kf⟩π​=⟨f,(I−K)f⟩π​=EK​(f).​
(1)
This is the probabilistic representation of the Dirichlet form of a Markov chain.

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