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Past exam of the mathematics course of the University of Cambridge / 2023 / iii / Paper 218 / 1 / c / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2023 iii Paper 218 1 c
2026-09-28  0 By others on same topic  0 Discussions Create my own version
With X having rows xiT​=(1,gi​,mi​) and μi​(β)=exiT​β, the quasi-score equation is
XT{Y−μ(β)}=0.
(1)
It is the same coefficient equation as for Poisson maximum likelihood, explaining why the two models have identical coefficient estimates.
Let W=diag(μ​1​,…,μ​n​) and let coordinate 2 denote gender. The model-based standard error is
se(β​1​)=ϕ​[(XTWX)−1]22​​,ϕ​=n−3XP2​​.
(2)

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