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Past exam of the mathematics course of the University of Cambridge / 2023 / iii / Paper 224 / 2 / c / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2023 iii Paper 224 2 c
2026-09-28  0 By others on same topic  0 Discussions Create my own version
Conditionally on X1n​=x1n​, the uniform index J selects the symbol a with probability Px1n​​(a). The law of total probability therefore gives
P(a)=P(XJ​=a)=∑x1n​∈B​Pn​(x1n​)Px1n​​(a)=∑x1n​∈B​Qn(B)Qn(x1n​)​Px1n​​(a).
(1)
Thus P is the conditional mean type of a string in B.

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