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Past exam of the mathematics course of the University of Cambridge
/
2023
/
iii
/
Paper 313
/
2
/
c
/
Solution
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Past exam of the mathematics course of the University of Cambridge
2023
iii
Paper 313
2
c
2026-09-28
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For
a
rotationally symmetric
vortex
, the
equation
away from the origin is
u
′′
+
r
1
u
′
=
e
u
−
1.
(1)
Insert
u
=
α
lo
g
r
+
β
+
γ
r
+
δ
r
2
+
⋯
.
(2)
The prescribed zero fixes
α
=
2
N
. Since
N
≥
1
,
e
u
=
e
β
r
2
N
[
1
+
o
(
1
)]
, while
u
′′
+
r
1
u
′
=
r
γ
+
4
δ
+
o
(
1
)
.
(3)
Matching the singular and
constant terms
with
e
u
−
1
=
−
1
+
o
(
1
)
gives
(
α
,
γ
,
δ
)
=
(
2
N
,
0
,
−
4
1
)
.
(4)
The undetermined
β
is fixed by matching this local expansion to
u
→
0
at
infinity
.
Ancestors
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c
2
Paper 313
iii
2023
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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