Past exam of the mathematics course of the University of Cambridge / 2023 / iii / Paper 324 / 4 / a / i / Solution

A computational-basis vector $|x_1{x}_2{x}_3⟩$ has eigenvalue $(-1{)}^{x_i+x_j}$ under $Z_i{Z}_j$. Simultaneous eigenvalue $+1$ for $Z_1{Z}_2$, $Z_2{Z}_3$, and $Z_1{Z}_3$ therefore requiresThe stabilizer subspace isIt is two-dimensional because the three displayed nonidentity stabilizers contain only two independent generators; indeed $(Z_1{Z}_2)(Z_2{Z}_3)=Z_1{Z}_3$.