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Past exam of the mathematics course of the University of Cambridge / 2023 / iii / Paper 342 / 1 / b / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2023 iii Paper 342 1 b
2026-09-28  0 By others on same topic  0 Discussions Create my own version
Since M2=nM, direct multiplication gives the matrix inverse
(In​+pM)−1=In​−1+npp​M,​
(1)
provided 1+np=0, as required by invertibility of the K-matrix. For q=eJ​,
K−1eJ​=eJ​−1+npp​1.
(2)
The attached gauge-flux vector is therefore
Φ=2πℏeJ​−1+np2πℏp​1.
(3)
Relative to the K=In​ electron in part a, every one of the n gauge fields consequently carries the additional flux
ΔΦI​=−1+np2πℏp​.​
(4)

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