Solution (source code)

= Solution

If $N=0$, then $|N-\mathbb EN|=\mathbb EN$. Hence the <Chebyshev inequality> gives
$$
\mathbb P(N=0)
\leq
\mathbb P\bigl(|N-\mathbb EN|\geq\mathbb EN\bigr)
\leq
\frac{\operatorname{var}(N)}{(\mathbb EN)^2}.
$$
The assumed <limit> therefore proves
$$
\boxed{\mathbb P(N=0)\longrightarrow0}.
$$
This is the <second moment method> in its simplest form.