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Mathematics course of the University of Cambridge

Past exam of the mathematics course of the University of Cambridge

2024

Paper 2

If $N=0$, then $|N-\mathbb EN|=\mathbb EN$. Hence the <Chebyshev inequality> gives
$$
\mathbb P(N=0)
\leq
\mathbb P\bigl(|N-\mathbb EN|\geq\mathbb EN\bigr)
\leq
\frac{\operatorname{var}(N)}{(\mathbb EN)^2}.
$$
The assumed <limit> therefore proves
$$
\boxed{\mathbb P(N=0)\longrightarrow0}.
$$
This is the <second moment method> in its simplest form.

Solution

Past exam of the mathematics course of the University of Cambridge / 2024 / ia / Paper 2 / 12F / iv / Solution

Past exam of the mathematics course of the University of Cambridge / 2024 / ia / Paper 2 / 12F / iv / Solution

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Past exam of the mathematics course of the University of Cambridge / 2024 / ia / Paper 2 / 12F / iv / Solution

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