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Past exam of the mathematics course of the University of Cambridge
/
2024
/
ia
/
Paper 3
/
10B
/
ii
/
Solution
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Past exam of the mathematics course of the University of Cambridge
2024
ia
Paper 3
10B
ii
Created
2026-09-24
Updated
2026-09-25
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Close the
surface
with the
unit disk
D
in the
plane
z
=
0
. Its outward normal is
−
e
z
, but
F
⋅
(
−
e
z
)
=
−
z
4
=
0
there. Also
∇
⋅
F
=
2
x
−
2
y
+
4
z
3
.
(1)
The
x
and
y
terms integrate to zero by
symmetry
. The
divergence theorem
therefore gives
∫
S
F
⋅
d
S
=
∫
0
2
π
∫
0
1
∫
0
1
−
r
2
4
z
3
r
d
z
d
r
d
θ
=
2
π
∫
0
1
r
(
1
−
r
2
)
4
d
r
=
5
π
.
(2)
Ancestors
(11)
ii
10B
Paper 3
ia
2024
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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