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Past exam of the mathematics course of the University of Cambridge / 2024 / ia / Paper 3 / 12B / ii / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2024 ia Paper 3 12B ii
Created 2026-09-24 Updated 2026-09-25  0 By others on same topic  0 Discussions Create my own version
A tensor is totally antisymmetric tensor if interchanging any two indices changes its sign. Consequently every component with repeated indices vanishes. In R3:
  • for n=2, the general tensor is Aij​=ak​ϵkij​, with three free components;
  • for n=3, it is Aijk​=aϵijk​;
  • for n>3, every component repeats an index, so the tensor is zero.
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