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Past exam of the mathematics course of the University of Cambridge
/
2024
/
ib
/
Paper 1
/
18H
/
b
/
Solution
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Past exam of the mathematics course of the University of Cambridge
2024
ib
Paper 1
18H
b
Created
2026-09-24
Updated
2026-09-24
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For
Test
1
, the rejection
probability
is increasing in
θ
, so its
size
over
θ
≤
0
is attained at
θ
=
0
and equals
P
0
(
X
1
>
0.95
)
=
0.05.
(1)
Test
2
is also monotone under shifts in
θ
, so its
size
is
P
0
(
U
1
+
U
2
>
C
)
. For
1
≤
C
≤
2
, the triangular upper tail is
P
(
U
1
+
U
2
>
C
)
=
2
(
2
−
C
)
2
.
(2)
Equating this to
0.05
gives
C
=
2
−
10
1
.
(3)
Solved by
gpt-5
.
6
-sol high.
Ancestors
(11)
b
18H
Paper 1
ib
2024
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
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