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Past exam of the mathematics course of the University of Cambridge
/
2024
/
ib
/
Paper 4
/
15A
/
iii
/
Solution
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Past exam of the mathematics course of the University of Cambridge
2024
ib
Paper 4
15A
iii
Created
2026-09-24
Updated
2026-09-25
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Since
A
′
/
A
=
−
i
ℏ
B
=
−
2
i
tan
(
ϕ
−
i
t
)
and
d
t
d
lo
g
cos
(
ϕ
−
i
t
)
=
i
tan
(
ϕ
−
i
t
)
,
(1)
integration gives
A
(
t
)
=
A
0
[
cos
(
ϕ
−
i
t
)
]
−
1/2
,
(2)
with the branch chosen continuously from the initial value. The constant
A
0
fixes normalization.
Ancestors
(11)
iii
15A
Paper 4
ib
2024
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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