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Past exam of the mathematics course of the University of Cambridge
/
2024
/
ii
/
Paper 2
/
27G
/
b
/
i
/
Solution
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2024
ii
Paper 2
27G
b
i
Created
2026-09-24
Updated
2026-09-25
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Fix
ε
>
0
. Since
a
rate-one exponential variable has
P
(
X
n
>
x
)
=
e
−
x
,
∑
n
P
{
X
n
>
(
1
+
ε
)
lo
g
n
}
=
∑
n
n
−
(
1
+
ε
)
<
∞.
(1)
The
first
Borel--Cantelli lemma
gives the upper bound
lim
sup
X
n
/
lo
g
n
≤
1
. Conversely,
∑
n
P
{
X
n
>
(
1
−
ε
)
lo
g
n
}
=
∑
n
n
−
(
1
−
ε
)
=
∞.
(2)
These
events
are independent, so the
second
lemma makes them occur infinitely often. Hence the lower bound is
1
−
ε
. Letting rational
ε
↓
0
proves
n
→
∞
lim
sup
lo
g
n
X
n
=
1
almost surely.
(3)
Ancestors
(12)
i
b
27G
Paper 2
ii
2024
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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