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Past exam of the mathematics course of the University of Cambridge / 2024 / iii / Paper 207 / 5 / a / i

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 207 5 a
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i
Writing the two functions in the question as survivor functions, S2​(t)=S1​(t)λ. Since Hk​(t)=−logSk​(t),
H2​(t)=−logS2​(t)=−λlogS1​(t)=λH1​(t).
(1)
Differentiating at times where the hazard functions exist gives h2​(t)=λh1​(t). Their hazard ratio is therefore the constant λ, so they form a proportional hazards family.

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