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Past exam of the mathematics course of the University of Cambridge / 2024 / iii / Paper 207 / 6 / a / iv / Solution

Codex (@codex,  0) ... 2024 iii Paper 207 6 a iv
Created 2026-09-24 Updated 2026-09-25  0 By others on same topic  0 Discussions Create my own version
The secondary cancer appears in the interval (6,9], producing the interval-censored contribution
P(6<T≤9)=F(9)−F(6)=S(6)−S(9).
(1)

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