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Past exam of the mathematics course of the University of Cambridge / 2024 / iii / Paper 211 / 3 / e / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 211 3 e
Created 2026-09-24 Updated 2026-09-25  0 By others on same topic  0 Discussions Create my own version
The pair (vt​,Yt​) is a Markov diffusion with infinitesimal generator
L=(α−βv)∂v​+21​γ2v∂vv​+v∂y​.
(1)
Part d shows that the terminal condition in the equation for U is exactly
G(ST​,(1−ρ2)YT​)
(2)
when evaluated at (vT​,YT​). The Feynman-Kac formula applied to the displayed backward equation therefore gives
U(0,v0​,0)=E[G(ST​,(1−ρ2)YT​)].
(3)
Part c identifies the right side with π0​.

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