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Past exam of the mathematics course of the University of Cambridge / 2024 / iii / Paper 301 / 1 / a / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 301 1 a
Created 2026-09-24 Updated 2026-09-25  0 By others on same topic  0 Discussions Create my own version
Under Aμ​↦Aμ​+∂μ​α, the field strength is unchanged, but the mass term in the Proca action changes by
2m2​{2Aμ∂μ​α+(∂α)2},
(1)
which is not generally a total derivative. The mass therefore breaks gauge invariance.
The Euler-Lagrange field equation is
∂μ​Fμν+m2Aν=0.
(2)
Taking its divergence and using the antisymmetry of Fμν gives m2∂ν​Aν=0. Since m>0, the Lorenz constraint in Proca theory follows. Substitution back into the field equation then gives
(□+m2)Aν=0,∂ν​Aν=0.
(3)

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