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Past exam of the mathematics course of the University of Cambridge
/
2024
/
iii
/
Paper 336
/
2
/
a
/
i
/
Solution
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2024
iii
Paper 336
2
a
i
Created
2026-09-28
Updated
2026-10-03
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At leading order,
u
=
R
cos
θ
,
u
t
=
−
R
sin
θ
,
(1)
so
f
=
−
u
(
u
t
)
2
=
−
R
3
cos
θ
sin
2
θ
.
(2)
The required period
averages
are
⟨
cos
θ
sin
3
θ
⟩
=
0
,
⟨
cos
2
θ
sin
2
θ
⟩
=
8
1
.
(3)
Hence
R
′
=
0
,
R
ϕ
′
=
8
R
3
.
(4)
The initial
data
give
R
(
0
)
=
1
and
ϕ
(
0
)
=
0
, so
R
(
T
)
=
1
,
ϕ
(
T
)
=
8
T
.
(5)
Thus the perturbation produces
a
slow
frequency
shift but no leading
amplitude
decay:
u
(
t
)
∼
cos
(
t
+
8
ϵ
t
)
.
(6)
Ancestors
(12)
i
a
2
Paper 336
iii
2024
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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