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Past exam of the mathematics course of the University of Cambridge
/
2024
/
iii
/
Paper 336
/
2
/
a
/
ii
/
Solution
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2024
iii
Paper 336
2
a
ii
Created
2026-09-28
Updated
2026-10-03
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Now
f
=
−
u
2
u
t
=
R
3
cos
2
θ
sin
θ
.
(1)
Therefore
R
′
=
−
R
3
⟨
cos
2
θ
sin
2
θ
⟩
=
−
8
R
3
,
(2)
whereas
R
ϕ
′
=
0
because
⟨
cos
3
θ
sin
θ
⟩
=
0
. Integrating with
R
(
0
)
=
1
gives
d
T
d
R
−
2
=
4
1
,
(3)
and hence
R
(
T
)
=
(
1
+
4
T
)
−
1/2
,
ϕ
(
T
)
=
0
.
(4)
The leading uniformly slow-decaying
oscillation
is
u
(
t
)
∼
(
1
+
4
ϵ
t
)
−
1/2
cos
t
.
(5)
Ancestors
(12)
ii
a
2
Paper 336
iii
2024
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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