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Past exam of the mathematics course of the University of Cambridge
/
2025
/
ia
/
Paper 3
/
12A
/
Solution
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Mathematics course of the University of Cambridge
Past exam of the mathematics course of the University of Cambridge
2025
ia
Paper 3
12A
Created
2026-09-23
Updated
2026-09-25
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The
product rule
gives
∂
j
(
T
ij
v
i
)
=
(
∂
j
T
ij
)
v
i
+
T
ij
∂
j
v
i
.
(1)
Integrating and applying the
divergence theorem
proves the identity.
Here
div
T
=
4
(
x
,
y
,
z
)
and
v
=
x
(
x
,
y
,
z
)
, so
∫
V
div
T
⋅
v
d
V
=
4
∫
V
x
(
x
2
+
y
2
+
z
2
)
d
V
=
3
7
.
(2)
On the boundary,
(
T
n
)
⋅
v
=
x
(
x
⋅
n
)
(
x
2
+
y
2
+
z
2
−
1
)
. The nonzero contributions from the faces
x
=
1
,
y
=
1
,
z
=
1
are respectively
2/3
,
5/12
,
5/12
, totaling
3/2
.
Finally, direct contraction gives
T
ij
∂
j
v
i
=
2
x
(
x
2
+
y
2
+
z
2
)
−
4
x
,
(3)
whose
integral
is
−
5/6
. Thus the right side is
3/2
−
(
−
5/6
)
=
7/3
, equal to the left side.
Ancestors
(10)
12A
Paper 3
ia
2025
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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