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Past exam of the mathematics course of the University of Cambridge
/
2025
/
ii
/
Paper 1
/
19J
/
d
/
Solution
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Past exam of the mathematics course of the University of Cambridge
2025
ii
Paper 1
19J
d
Created
2026-09-24
Updated
2026-09-25
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Take
t
↦
A
and
r
↦
B
. Then
A
2
=
I
and
A
B
A
−
1
=
(
1
0
−
1
1
)
=
B
−
1
,
(1)
so these
matrices
define
a
representation. The line
C
e
1
is fixed by both
matrices
and is
a
one-dimensional
subrepresentation
.
Any complementary line
has a
generator
e
2
+
c
e
1
. But
B
(
e
2
+
c
e
1
)
=
e
2
+
(
c
+
1
)
e
1
,
(2)
which cannot lie on the same line. Thus no complement is
B
-invariant, and therefore no
G
-invariant complement exists.
Ancestors
(11)
d
19J
Paper 1
ii
2025
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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