Fix and choose with on . The sequence is bounded in . By part (a), each subsequence has a further subsequence converging strongly in on this bounded interval. The original weak convergence in forces every such strong limit to be zero. It follows that the whole sequence satisfies
otherwise a subsequence bounded away from zero would contradict the preceding compactness argument.
The pointwise hypothesis gives a uniform tail estimate:
whose right-hand side tends to zero as , independently of . Given , first choose so that this tail is below , and then choose so that the integral on is below . Therefore

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