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Past exam of the mathematics course of the University of Cambridge / 2025 / ii / Paper 2 / 39D / v / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2025 ii Paper 2 39D v
Created 2026-09-24 Updated 2026-09-25  0 By others on same topic  0 Discussions Create my own version
Integrating the traction over the sphere gives
F=∫r=a​σ⋅ndS=−2a3μ​U(4πa2).
(1)
Hence the force exerted by the fluid on the sphere is
F=−6πμaU.​
(2)
This is Stokes' drag law; the sign is opposite to the sphere's velocity.

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