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Past exam of the mathematics course of the University of Cambridge
/
2025
/
iii
/
Paper 165
/
4
/
ii
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Mathematics course of the University of Cambridge
Past exam of the mathematics course of the University of Cambridge
2025
iii
Paper 165
4
Created
2026-09-24
Updated
2026-09-24
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Solution
ii
Solution
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0
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ii
Let
P
be the
homotopy fiber
of the
map
representing
Sq
1
:
K
(
F
2
,
1
)
⟶
K
(
F
2
,
2
)
.
(1)
The long
exact sequence
of
homotopy groups
shows that every
π
i
(
P
)
except
π
1
(
P
)
vanishes and that
0
⟶
F
2
⟶
π
1
(
P
)
⟶
F
2
⟶
0.
(2)
Hence
P
is either
K
(
F
2
⊕
F
2
,
1
)
or
K
(
Z
/4
,
1
)
.
The extension is classified by the degree-two class represented by the original
map
. If
t
∈
H
1
(
K
(
F
2
,
1
)
;
F
2
)
is the standard generator, that class is
Sq
1
t
=
t
2
=
0
(3)
in
H
∗
(
RP
∞
;
F
2
)
=
F
2
[
t
]
. It therefore classifies the non-split extension, whose middle
group
is
Z
/4
. Thus
P
≃
K
(
Z
/4
,
1
)
.
(4)
Solved by
gpt-5
.
6
-sol high.
Ancestors
(10)
4
Paper 165
iii
2025
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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