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Past exam of the mathematics course of the University of Cambridge / 2025 / iii / Paper 221 / 4 / b / i

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2025 iii Paper 221 4 b
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i
Write mz​(X)=μz​(X,βz​) and e(X)=e(X;α). Conditional on X,
μ​1dr​(X)=m1​(X)+e(X)e(X)​(μ1​(X)−m1​(X)),
(1)
with the analogous control expression
μ​0dr​(X)=m0​(X)+1−e(X)1−e(X)​(μ0​(X)−m0​(X)).
(2)
If the propensity model is correct, both ratios are one and these equal μ1​(X) and μ0​(X), so their difference is the conditional average treatment effect.

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