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Past exam of the mathematics course of the University of Cambridge / 2025 / iii / Paper 304 / 2 / a / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2025 iii Paper 304 2 a
Created 2026-09-24 Updated 2026-09-25  0 By others on same topic  0 Discussions Create my own version
Completing the square in the Gaussian functional integral and choosing
N−1=∫Dϕexp(i∫d4xLb​)
(1)
normalizes Z0​[0]=1. The result is
Z0​[J]=exp[−21​∫d4x,d4yJ(x)DF​(x−y)J(y)],
(2)
where the Feynman propagator in the convention of the question is
DF​(x−y)=∫(2π)4d4p​p2−M2+iϵi,e−ip⋅(x−y)​.
(3)

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