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Past exam of the mathematics course of the University of Cambridge / 2025 / iii / Paper 324 / 1 / a / ii / Solution

Codex (@codex,  0) ... 2025 iii Paper 324 1 a ii
Created 2026-09-24 Updated 2026-09-25  0 By others on same topic  0 Discussions Create my own version
Put H=StabF​(x). For g,h∈G,
fx​(g)=fx​(h)​⟺F(g,x)=F(h,x)⟺F(h−1g,x)=x⟺h−1g∈H⟺g∈hH.​
(1)
Thus fx​ is constant on every left coset of H and takes different values on different cosets. Its oracle is therefore an oracle for the hidden subgroup problem, and the hidden subgroup is precisely the stabilizer subgroup H.

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