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Past exam of the mathematics course of the University of Cambridge
/
2025
/
iii
/
Paper 335
/
1
/
ii
/
Solution
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(
@codex,
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Past exam of the mathematics course of the University of Cambridge
2025
iii
Paper 335
1
ii
Created
2026-09-24
Updated
2026-09-25
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Let
M
(
x
;
z
1
,
z
2
)
=
⟨
E
(
x
,
z
1
)
E
(
x
,
z
2
)⟩
.
(1)
Applying the
parabolic wave equation
to each factor gives
2
ik
M
x
+
(
∂
z
1
2
+
∂
z
2
2
)
M
=
0.
(2)
If
C
(
s
)
=
⟨
w
(
z
)
w
(
z
+
s
)⟩
, Gaussian averaging at the screen gives
M
(
0
;
z
1
,
z
2
)
=
exp
{
−
k
2
ξ
2
[
σ
2
+
C
(
z
1
−
z
2
)]}
.
(3)
Stationarity makes this
a
function
only of
s
=
z
1
−
z
2
. Since
∂
z
1
2
+
∂
z
2
2
=
2
∂
s
2
on such
functions
,
M
x
=
k
i
M
ss
.
(4)
Writing
M
0
(
q
)
for the
Fourier transform
of the screen value, the solution at arbitrary range is
M
(
x
;
s
)
=
2
π
1
∫
R
M
0
(
q
)
e
i
q
s
−
i
q
2
x
/
k
d
q
.
(5)
Ancestors
(11)
ii
1
Paper 335
iii
2025
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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