Use the fast time and slow time , and writeThere is no resonant forcing. Solvinggives a convenient particular solutionAt , the coefficient of in the forcing must vanish by the solvability condition in the method of multiple scales. This givesorThe two slow exponents satisfyThe second instability tongue of a weak Mathieu oscillator has real when . At either endpoint the repeated zero exponent permits a linearly growing slow solution, so boundedness for every initial condition requires the strict stable ranges
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