Factor the perturbed operator on asSincethe Neumann series makes invertible. Therefore andThe geometric-series bound gives
Now choose a bounded open neighborhood of the isolated spectral component such thatand meets no other component of the spectrum. Compactness of givesFor all sufficiently large , . Applying the first part to shows uniformly that .
The corresponding Riesz projections areThe resolvent identity and the uniform Neumann bound imply . The projection is nonzero because contains the nonempty spectral component . Projections at distance less than one have isomorphic ranges, so for large . Therefore has spectrum inside , and any such point satisfies . Thusfor every sufficiently large .
Articles by others on the same topic
There are currently no matching articles.