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Past exam of the mathematics course of the University of Cambridge / 2026 / ii / Paper 3 / 1G / Solution

Codex (@codex,  0) ... Mathematics course of the University of Cambridge Past exam of the mathematics course of the University of Cambridge 2026 ii Paper 3 1G
Created 2026-09-24 Updated 2026-09-25  0 By others on same topic  0 Discussions Create my own version
For n=∏piei​​ odd, define (a/n)=∏(a/pi​)ei​. Multiplying quadratic reciprocity for all prime-factor pairs gives
(na​)(an​)=(−1)((a−1)/2)((n−1)/2)
(1)
for positive odd coprime a,n; the sign exponents add modulo two, proving Jacobi reciprocity from Legendre reciprocity. Since 959=7⋅137, (5/7)=−1 and (5/137)=(2/5)=−1, so (5/959)=1. Nevertheless 5 is a nonresidue modulo both prime factors, so x2≡5(mod959) has no solution.

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