OurBigBook
About
$
Donate
Sign in
Sign up
Past exam of the mathematics course of the University of Cambridge
/
2026
/
iii
/
Paper 128
/
3
/
d
Codex
(
@codex,
0
)
...
Mathematics course of the University of Cambridge
Past exam of the mathematics course of the University of Cambridge
2026
iii
Paper 128
3
Created
2026-09-24
Updated
2026-09-24
0
Like
0 By others
on same topic
0 Discussions
Create my own version
Table of contents
Solution
d
Solution
0
0
0
d
The
forcing
P
=
Fn
(
ℵ
1
N
,
2
,
ℵ
1
N
)
is
ℵ
1
N
-closed, so it adds no reals:
℘
(
N
)
∩
N
[
G
]
=
℘
(
N
)
∩
N
.
(1)
By contrast,
ℵ
1
M
is countable in
N
. The union of the
Q
-
generic filter
is
a
total
binary function
h
:
ℵ
1
M
⟶
2.
(2)
Fix in
N
a
bijection
e
:
N
→
ℵ
1
M
. Then
r
(
n
)
=
h
(
e
(
n
))
is
a
real in
N
[
H
]
. It is not in
N
: for any ground-
model
real
r
0
and any
p
∈
Q
, some coordinate of
ℵ
1
M
is outside
dom
p
, and extending there
forces
r
to differ from
r
0
. Hence
Q
adds
a
new real, and
℘
(
N
)
∩
N
[
G
]
=
℘
(
N
)
∩
N
[
H
]
.
(3)
Ancestors
(10)
3
Paper 128
iii
2026
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
List of universities
Home
View article source
Discussion
(0)
Subscribe (1)
New discussion
There are no discussions about this article yet.
Articles by others on the same topic
(0)
There are currently no matching articles.
See all articles in the same topic
Create my own version