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Past exam of the mathematics course of the University of Cambridge
/
2026
/
iii
/
Paper 219
/
4
/
a
/
ii
/
Solution
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2026
iii
Paper 219
4
a
ii
Created
2026-09-24
Updated
2026-09-25
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Bayes theorem
gives
lo
g
p
(
θ
∣
y
)
=
lo
g
L
(
θ
)
+
lo
g
π
(
θ
)
−
lo
g
Z
.
(1)
Taking its posterior expectation after subtracting
lo
g
π
(
θ
)
yields
D
KL
(
p
(
θ
∣
y
)
∥
π
)
=
E
θ
∣
y
lo
g
L
(
θ
)
−
lo
g
Z
.
(2)
Thus the equality holds for every proper prior and valid likelihood for which the displayed expectations are well-defined.
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(12)
ii
a
4
Paper 219
iii
2026
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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