The family is a Gaussian random field. For distinct its covariance is
Two distinct vertices of have a common neighbour exactly when their graph distance, equivalently their distance, is two. Since jointly Gaussian variables are independent exactly when they are uncorrelated,
Thus the field has finite-range dependence, even though nearest-neighbour values are independent.
Solved by gpt-5.6-sol high.
Write ; because , as . Every path in a graph of length contains, by a greedy selection, at least vertices at mutual graph distance greater than two, where . The corresponding field values are jointly independent by part (a). Hence the probability that a fixed path lies in the superlevel set is at most
There are at most length- paths from the origin. The union bound therefore gives
Choose a finite for which and let . There is then no unbounded component through the origin, and translation invariance rules out an unbounded component anywhere almost surely. Thus the critical threshold for level-set percolation satisfies .
Solved by gpt-5.6-sol high.
The one-arm event depends on the field values in the finite ball . Replace by for . In the new variables the event has threshold zero, while the product normal distribution density is . Differentiating this finite-dimensional integral under the integral sign gives the Gaussian shift identity
This is also an instance of Gaussian integration by parts. In particular, the asserted inequality holds, in fact with equality.
Solved by gpt-5.6-sol high.
Apply the OSSS inequality to the independent coordinates and to the indicator of the one-arm event . Use the randomized OSSS exploration of a one-arm event: choose uniformly from and reveal the variables needed to explore the superlevel cluster meeting . A coordinate can be revealed only if a nearby vertex has an open connection over the relevant distance. Translation invariance, finite-range dependence and the union bound therefore give the revealment estimate
for both kinds of coordinates, after enlarging the explored neighbourhood by a distance depending only on .
For an increasing Gaussian threshold event, the resampling influence of is bounded by a universal constant times . The influence of is bounded by the sum of the corresponding influences at the neighbours of : indeed Gaussian integration by parts gives
first for smooth increasing approximations and then by a limit. Consequently the OSSS bound becomes
Part (c) identifies the final sum with . Dividing and putting proves
Solved by gpt-5.6-sol high.

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