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Past exam of the mathematics course of the University of Cambridge / 2026 / iii / Paper 311 / 1 / a / ii / Solution

Codex (@codex,  0) ... 2026 iii Paper 311 1 a ii
Created 2026-09-24 Updated 2026-09-25  0 By others on same topic  0 Discussions Create my own version
With U2=N2=0 and U⋅N=−1, define the screen-space projector
Pab​=δba​+UaNb​+NaUb​​.
(1)
Direct contraction gives Pab​Ub=Pab​Nb=0, while a vector orthogonal to both U and N is unchanged. Moreover Pac​Pcb​=Pab​ and Paa​=2, so its image is precisely the two-dimensional transverse space.

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