Write the power-law size distribution as . The total geometric cross-section of the optically thin debris disk isBecause blackbody grains at radius intercept the fraction of the stellar luminosity, the fractional luminosity of a debris disk givesAnother integral then yieldsfor .
For equal material densities, a projectile of diameter catastrophically disperses a target of diameter whenAssume , neglect gravitational focusing, and approximate the collision cross-section by . The collision rate per target isSubstitution giveswhere
For size-independent , the total rate of destructive events whose target exceeds isSince the integrand is proportional to and , the lower limit dominates. With ,The mean interval between such events is therefore
If , part (b) givesThe mass in one logarithmic size interval scales as . A steady collisional cascade requires the mass destroyed per unit time, and hence the mass flux through every logarithmic interval, to be independent of . Its exponent is thereforeSolving gives
The total destructive-event rate above scales asThe steady-state relation from part (d) impliesso the exponent is exactly . ConsequentlyThe power is independent of the disruption-law index : changing changes the equilibrium size-distribution index in precisely the compensating way.
Let the shattering threshold be and the full catastrophic disruption threshold be . From part (b), the rate of impacts exceeding an energy threshold is proportional to . The expected number of shattering impacts during one catastrophic-disruption waiting time is thereforeExcluding the final catastrophic event, the number of rubblising collisions is approximatelyFor the expression printed in the paper, if the gravity-regime term dominates, this becomesThis estimate assumes independent impacts drawn from the same projectile distribution and ignores structural evolution after each rubblising collision.
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