Past exam of the mathematics course of the University of Cambridge / 2026 / iii / Paper 353 / 3 / vii

Table of contents
- Solution vii

Solution

The second components of

e_{-}

and

e_{+}

have opposite signs. Therefore

⟨ ψ_{q} (t)⟩ = \frac{ϕ _{q} ( 0 )}{2} [- e^{- (s - c) t} + e^{- (s + c) t}] = - ϕ_{q} (0) e^{- s t} sinh (c t) .

Solved by gpt-5.6-sol high.

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