Past exam of the mathematics course of the University of Cambridge 2009 iii Paper 43 4 1 Solution Created 2026-10-03 Updated 2026-10-14
Assume short-range ferromagnetic exchange and zero external field. In the one-dimensional Ising model, a domain wall costs only , independent of the lengths of the domains it separates. There are order- positions for one wall, so its positional entropy offsets any finite energy cost at nonzero temperature as the system grows. Domain walls consequently have a positive density at every , destroying a uniform spontaneous spin magnetization. Periodic boundaries require an even number of walls, but that constraint does not remove their nonzero thermodynamic-limit density.
The One-dimensional Ising correlation function makes this argument explicit. A bond is broken with probability , and the infinite-chain correlation isThe dominant eigenvalue of the transfer matrix for the one-dimensional Ising model is , so the free energy per spin is analytic for . There is no finite-temperature transition in one dimension; only the zero-temperature limit orders.
In two dimensions a reversed cluster is enclosed by a Peierls contour. A contour of length costs , while the number of such contours surrounding a fixed site grows at most as a polynomial in times : after the initial edge, a nonbacktracking square-lattice walk has at most three choices per step. With plus boundary conditions, flipping the interior of a specified contour yields the Boltzmann suppression . ThereforeFor sufficiently low temperature this bound is below , giving a positive spontaneous magnetization. This is the energy-entropy mechanism of the Peierls argument.
At sufficiently high temperature, the graphical expansion bounds correlations by sums of connecting paths weighted by . The same nonbacktracking count converges geometrically when , giving exponential decay and a disordered phase. Since an ordered low-temperature phase and a disordered high-temperature phase both occur, the two-dimensional model has a finite-temperature phase transition. The argument establishes its existence and the dimensional distinction, not the exact value of its critical temperature.
Past exam of the mathematics course of the University of Cambridge 2023 iii Paper 209 4 a i Solution Created 2026-09-28 Updated 2026-10-03
Under plus boundary conditions, if , the negative cluster containing the origin is surrounded by a Peierls contour . Flipping all spins inside is injective after is specified and increases the Boltzmann weight by . ThereforeThe number of length- contours surrounding the origin is at most , so the sum tends to zero as , uniformly in . For sufficiently large it is below , and then