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The larger value for the carbonyl bond means that its dissociation costs $167\mathrm{kJ}\mathrm{mo}{\mathrm{l}}^{-1}$ more for the supplied comparison. A carbonyl combines a strong sigma bond with efficient pi overlap between spatially compatible C 2p and O 2p orbitals. This gives a substantial localized multiple-bond contribution.

The short P–O linkage in a phosphine oxide is also strong, but it is more polar, with a substantial ${\mathrm{P}}^{+}-{\mathrm{O}}^{-}$ contribution. P 3p and O 2p orbitals have less favourable radial and energy matching than C 2p/O 2p for a simple localized pi bond. oxygen donation into P–R antibonding orbitals adds stabilization, but it is not identical to the carbonyl pi bond. Therefore the formal double-bond notation does not imply equal bond strength. A substantial P-3d contribution is not needed to explain the bonding. The stated bond-dissociation values compare complete dissociation processes, so their magnitudes should not be derived solely from one overlap integral or from the two atoms' electronegativity difference.

Treat this as standalone organophosphorus chemistry. The phosphorus(III) lone pair attacks the terminal nitrogen of the organic azide. Cyclization of the initial phosphazide and loss of nitrogen give an iminophosphorane:The ortho amide provides a neighboring acidic NH proton and a carbonyl oxygen donor. A proton relay to the imino nitrogen and intramolecular O$\to$P attack generate a five-membered, O-bound pentacoordinate phosphorus intermediate. Water can then attack phosphorus, with proton transfer to nitrogen, followed by P–N cleavage and opening of the neighboring-group contact.

The overall hydrolysis products areThe carbonyl group assists the hydrolysis and is regenerated; the product is an aniline and the ortho-carboxamide phosphine oxide, rather than an amide-linked ligation product. The favorable five-membered intramolecular interaction and proton delivery help hydrolyze a normally rather persistent aryl iminophosphorane. This explanation concerns only the printed chemical transformation.

Let $L^{-}=\mathrm{P}{\mathrm{h}}_2\mathrm{P}(\mathrm{O})\mathrm{CH}=\mathrm{C}(\mathrm{tBu})\mathrm{N}{\mathrm{H}}^{-}$, with its O and N donors available for lithium coordination. A plausible symmetric tetramer has a Li${}_4$O${}_4$ cubane-type core, with alternating Li and phosphoryl O vertices and an additional enamide N donor attached to each Li. The O,N-chelating Ligand in coordination chemistry can be arranged equivalently around the aggregate, consistent with one ${}^7$Li environment. This is a connectivity model, not a uniquely reconstructed diffraction structure.

The initially formed nitrile-addition product has an acidic $\mathrm{C}{\mathrm{H}}_2$ group next to the phosphine oxide. Transfer of one of these protons to the nitrile-derived N gives a delocalized lithiated enamide, reinforced by O,N coordination and organolithium aggregation. The organic framework becomes $\mathrm{P}(\mathrm{O})-\mathrm{CH}=\mathrm{C}(\mathrm{tBu})-\mathrm{NHLi}$.

Assign ${\delta }_H=4.82$ to the vinylic CH and ${\delta }_H=3.25$ to NH. Each integrates to one proton, as required after hydrogen migration. Their singlet appearance does not mean that the original carbon has become a freely rotating, equivalent-proton methylene group.

The phosphine oxide $\mathrm{M}{\mathrm{e}}_3\mathrm{PO}$, with three P–C bonds and one terminal P–O bond.