Past exam of the mathematics course of the University of Cambridge 2014 iii Paper 6 2 iii Solution Created 2026-10-03 Updated 2026-10-06
Let be the quotient map. Since is norm closed and has finite codimension, the quotient is a finite-dimensional normed space. Choose a basis of its continuous dual and compose its coordinate linear functionals with . This gives such thatIf , it vanishes on . Evaluation at is weak-star continuous, and is weak-star dense, so it vanishes on all of . The dual norm formula gives . Hence .
Assume ; the zero space is trivially normed by any positive constant. We claim thatIf not, there would be and with . The sequence is bounded. Finite-dimensionality of gives a norm-convergent subsequence with limit . Then , and is norm closed because is Banach. Thus and , a contradiction. This is positive distance between a unit sphere and a disjoint finite-dimensional subspace.
Fix , identifying it with , and put . On , define . The distance definition givesThe Hahn-Banach theorem extends it to with , and .
Apply part (ii) with the Banach space , its finite-dimensional dual vector subspace , and the bidual space element . For every it supplies satisfyingThus . Normalize by and let to obtainHomogeneity gives, for all ,Consequently a finite-codimensional weak-star dense dual subspace is norming, with . Since is a real linear vector subspace and its ball is symmetric, the same supremum is obtained if an absolute value is inserted. The argument uses near-unit interpolation and a limiting supremum, not an assertion that the supremum is attained.