Linear equivalence of divisors Created 2026-09-24 Updated 2026-10-03
Two divisors and are linearly equivalent, written , when is a principal divisor. Multiplication by a rational function whose divisor is gives an isomorphism between their spaces of sections, so .
For a nonsingular projective integral curve, apply the Riemann-Roch theorem to the divisor on an algebraic curve . It gives , where is the geometric genus. For sufficiently large , this exceeds the dimension of the space of constant functions; over the usual geometrically integral convention that dimension is one. Thus contains a nonconstant rational function.
By the definition of , the principal divisor on an algebraic curve of that function plus is effective, so it has no pole away from . Therefore there is a nonconstant rational function regular on . If is not a rational point, using its closed-point degree in the same inequality handles that case. A positive pole order at is unavoidable, since regular functions on a projective integral curve are constant in its constant field.
For a divisor on an algebraic curve over an algebraically closed field, its degree is
For a nonzero rational function , its principal divisor is
where zeros have positive order and poles have negative order.
Now let have degree zero on the projective line. Choose a homogeneous linear form whose zero is . Since , the expression
is homogeneous of degree zero and therefore defines a rational function on . Each has one simple zero, and the cancellation of total degree removes any common scaling ambiguity, so
Thus every degree-zero divisor on is principal. If and have the same degree, then is principal, whence
This is the divisor class on the projective line.
Write . The coordinate has no critical zero or pole in the finite chart. Near infinity use ; then
Hence the rational differential has one double pole at infinity and no other zero or pole:
which represents the canonical divisor of the projective line.
If , then , and linear equivalence of divisors gives . A function in the latter space has no finite poles, so it is a polynomial, and its degree is at most . Therefore
This calculation uses only the rational functions on , rather than the Riemann-Roch theorem.
Finally, suppose distinct satisfy . The function has one simple pole and therefore defines a degree-one finite morphism . A degree-one finite morphism between smooth projective curves is an isomorphism. It would follow that and hence that has genus zero, contrary to the hypothesis. Thus the principal divisor with one simple zero and one simple pole cannot occur on :
Let be a smooth plane cubic whose identity is an inflection point. A line through and , using the tangent when , has a third intersection counted with multiplicity. The chord-and-tangent group law defines by drawing the line through and and taking its third intersection.
The clean verification of the group axioms uses divisors. The line at infinity meets a Weierstrass cubic in , so three collinear points satisfy
Consequently the map
sends the chord-and-tangent construction to addition of divisor classes. The principal divisor criterion on an elliptic curve shows that this map is bijective. Associativity and commutativity therefore follow from the abelian group law on . The tangent convention handles repeated intersections, represents the zero class, and the third point on the line through and represents the inverse of . Hence all group axioms hold.
Principal Weil divisor Created 2026-10-06 Updated 2026-10-07