Past exam of the mathematics course of the University of Cambridge 2003 iii Paper 9 2 Solution 2026-10-14
Write a Blaschke product as , where , , and the zeros are counted with multiplicity. With normalized angular measure , Jensen's formula for each Blaschke factor givesIndeed, the mean of is , while has mean zero by the mean value property for harmonic functions. Each factor has modulus at most one. Applying the monotone convergence theorem to the negative logarithms of the finite products yields the radial logarithmic mean of a Blaschke product:The Blaschke condition implies : only finitely many zeros have modulus below , and for . Every summand tends to zero and is bounded in absolute value by . The dominated convergence theorem for this series, together with , therefore givesThis also covers finite products and constant unimodular products. Zeros on a circle create integrable logarithmic singularities and do not change the conclusion.
For a holomorphic function on the unit disc, this boundary condition characterizes Blaschke products, including unimodular constants. The nondecreasing radial means of the nonnegative subharmonic function must vanish, so . In the Blaschke factorization of a bounded holomorphic function , both logarithmic means tend to zero. The mean value property for harmonic functions applied to gives , and the maximum modulus principle makes unimodular constant. The converse follows from the radial logarithmic mean of a Blaschke product. Omitting the outer absolute value changes the condition: has zero mean logarithmic modulus, but is not a Blaschke product.