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At $\epsilon =0$ the algebraic poles are $\boxed{{\omega }_{\pm }^{(0)}=\pm 1}$; a retarded limiting prescription displaces them infinitesimally below the real axis. Set ${\omega }_s=s+{\delta }_s$, with $s=\pm 1$ and ${\delta }_s=O(\epsilon )$. The denominator becomesConsequentlyFor positive $\epsilon$ these two poles move below the real axis, giving slowly damped oscillations. For negative $\epsilon$ they move above it and the slow oscillations grow. This is only the slow part of the radiation-reaction oscillator pole structure; the third pole must still be examined.

For positive $\epsilon$, the real-axis frequency response of the radiation-reaction oscillator pole structure excludes future runaway growth but retains an upper-half-plane pole. Closing its inverse Fourier transform upward at $t<0$ gives a nonzero response before the force. The fast pole contributes approximately $\epsilon e^{t/\epsilon }$ for negative $t$. A strictly causal retarded prescription instead includes an exponentially growing term for positive $t$ and requires a Laplace transform contour. The pre-response is a consequence of imposing boundedness at future infinity, not an unavoidable property of all initial-value solutions of the differential equation.