Write a source and target in Schmidt decomposition with squared coefficients and , where . If , Nielsen's pure-state conversion theorem allows deterministic conversion. If , the Schmidt-tail entanglement monotone gives . Alice attains this bound with a local two-outcome measurement in quantum mechanics whose success Kraus operator is and whose failure operator is . They obey . The successful unnormalized state is times the target, and failure leaves a product state. A classical message tells Bob which branch occurred. Known local changes of Schmidt bases allow the same protocol for arbitrary two-qubit pure states with these coefficients.
Past exam of the mathematics course of the University of Cambridge 2010 iii Paper 51 3 b Solution Created 2026-10-03 Updated 2026-10-14
An upper bound follows directly from the Schmidt-tail entanglement monotonewhere is the reduced density matrix of a bipartite pure state. On these two-qubit states, this is the smaller squared Schmidt coefficient, so and .
Here is the average-monotonicity argument needed for all LOCC strategies. The largest eigenvalue is convex: for any unit vector , , and maximizing the left side gives the claim. Hence is concave. If Alice makes a local measurement, Bob's conditional reductions average to his original reduction. Concavity therefore gives . If Bob measures, use Alice's reductions instead. The two reductions of a pure state have the same nonzero eigenvalues by the Schmidt decomposition. Refining all measurement outcomes into individual Kraus operators keeps conditional states pure; iterating the inequality covers adaptive rounds of classical communication. The same bound persists for limits of such protocols.
If success produces the target with probability , its contribution to the final average is . Failure branches have nonnegative . ThusThis is a bound on arbitrary local protocols, not merely on a particular filtering measurement.