Past exam of the mathematics course of the University of Cambridge 2001 iii Paper 15 1 Solution Created 2026-10-03 Updated 2026-10-14
At a point , the complex tautological line bundle has fiber . The hyperplane line bundle is its dual, , and . On let be the tautological frame and its dual. On overlaps . The sheaf of holomorphic sections of a vector bundle of this dual bundle is the sheaf .
If a nonzero linear form cuts out the projective hyperplane , it gives a holomorphic section of with a simple zero along . Dividing a local section by gives a meromorphic function with no poles away from and at most a simple pole on . Conversely multiplication by turns such a function into a holomorphic section. These mutually inverse local constructions agree on overlaps and prove the holomorphic line bundle associated to a divisor identification
The nonnegative hyperplane twist cohomology by restriction calculation givesTo derive it from the permitted vanishing, use the hyperplane exact sequence for twisting sheaveswhere and . Local multiplication by a defining equation is injective, and restriction gives exactly its cokernel. Induct on , starting from a point, and then on . For , higher sheaf cohomology vanishes by assumption and global holomorphic functions are constant by compactness and the maximum principle. For , the long exact sequence in sheaf cohomology, the inductive vanishing for and the dimension induction on give vanishing in every positive degree andSumming this recurrence gives . Homogeneous degree- monomials give that many independent sections, so they form a basis. The printed extra equality to zero cannot hold in degree zero, already because ; the boxed calculation gives the intended dimensions.
For the differential of the projective quotient map, the differential of a smooth map is computed by applying a tangent vector to coordinate functions. Since ,ThusUnder replacing by , on a constant ambient tangent vector scales by , while a homogeneous linear form scales by . Therefore is independent of the representative. Its chart coefficients are holomorphic, so it is a global holomorphic vector field. The radial Euler vector field lies in the kernel of , either from the same formulas or because it differentiates a scaling orbit. Hence
Describe the Euler sequence on complex projective space fiberwise as well as in coordinates. At a line , the middle bundle has fiber and the holomorphic tangent bundle has fiber . Send a homomorphism to its composition with the quotient. The map from sends a scalar to that scalar times the inclusion . In homogeneous notation these maps areA local section of is a local degree-one homogeneous function on the punctured cone, so the second expression is representative-independent. Quotienting is surjective, and its kernel consists exactly of scalar inclusion maps. This proves the short exact sequence of locally free sheavesSince it is locally split, dualizing and tensoring by preserves exactness and gives the cotangent Euler sequence in homogeneous coordinatesOn global sections the last map identifies with the basis of linear forms in . Its kernel is zero. This proves the vanishing of global sections of the once-twisted projective cotangent bundle; left exactness gives .
Past exam of the mathematics course of the University of Cambridge 2007 iii Paper 56 4 Solution Created 2026-10-03 Updated 2026-10-14
Let be homogeneous coordinates on the complex projective line. The complex tautological line bundle has fibre the line over that point. Its dual is the hyperplane line bundle . Define the tensor powers of the hyperplane line bundle by for , the trivial line bundle for , and the appropriate power of for .
An explicit holomorphic line bundle construction uses the two charts and with coordinates and . Choose holomorphic local frames related on the overlap byThis is consistent with the tautological frames and for . A holomorphic section of is represented by entire chart functions satisfyingExpand . Holomorphicity of at requires every power with to vanish. Thus for , is exactly a polynomial of degree at most . Conversely every such polynomial gives an entire . Its coefficients supply the explicit isomorphismEquivalently, the global holomorphic sections are the homogeneous polynomials . For , the same chart argument gives no nonzero global section.
For the first cohomology, use the sheaf of holomorphic sections of a vector bundle and its Čech cohomology on this two-chart cover. A zero-cochain is a pair of entire chart functions . A one-cochain is a function holomorphic on , multiplied by . There are no alternating two-cochains on a two-set cover, so every one-cochain is a cocycle. The coboundaries areConsequently the holomorphic Laurent-series cohomology of twists on the projective line isHere the last term means the set of functions with entire. The charts and their intersection are Stein manifolds; Cartan theorem B makes this cover acyclic for the line-bundle section sheaf, so this Čech group computes the sheaf cohomology.
Every on has a Laurent series converging normally on compact annuli. Its nonnegative-power tail is an entire function of and can be removed by a finite-chart coboundary. Its tail with can be removed by : the series is entire in , because the inner Laurent radius is zero. Assign any overlapping removable powers to just one tail. The only possible remaining powers satisfy .
If , there is no such integer, proving the requested vanishing:For completeness, if , the remaining classes have basis and dimension . None can be a coboundary, by uniqueness of Laurent coefficients. This also explains exactly why is the threshold.
Finally, a global holomorphic section of is a pair of linear homogeneous polynomials:It vanishes at a projective point precisely when the nonzero vector belongs to the kernel of the coefficient matrix . If has rank two there is no zero; if the section vanishes everywhere. Exactly one projective zero occurs precisely when the kernel is a one-dimensional line. Thus the rank-one sections of two hyperplane line bundles are characterized byEquivalently, , where is a fixed nonzero vector and is a nonzero section of . Its single simple zero is the zero of . This includes the case when one component is identically zero and the other is a nonzero linear form.
Past exam of the mathematics course of the University of Cambridge 2015 iii Paper 18 5 a Solution Created 2026-10-03 Updated 2026-10-06
For a holomorphic vector bundle , the sheaf of vector-bundle-valued differential forms iswhere sections are smooth and restrictions are the usual ones. In a holomorphic local frame of , the Dolbeault operator acts coefficientwise and satisfies . Its Dolbeault cohomology with values in a holomorphic vector bundle is the cohomology of the global section complex .
The bundle-valued Dolbeault theorem identifies this with sheaf cohomology:Here is the sheaf of holomorphic differential forms, and is the sheaf of holomorphic sections of a vector bundle. Equivalently, the complexis a fine sheaf resolution, by the local Dolbeault-Poincaré lemma and smooth partitions of unity. In particular computes ; for the holomorphic differential-form factor must be retained.