Past exam of the mathematics course of the University of Cambridge 2003 iii Paper 65 4 ii Solution Created 2026-10-03 Updated 2026-10-14
At fixed time write the azimuthal shift as modulo . Integrating a radial derivative over the box gives a boundary difference proportional toThe two integrals agree by translation invariance of an integral over a full azimuthal period. Hence . The ordinary periodic boundary conditions make the and boundary differences zero as well. Finally,for every . Thus the volume averages in a shearing box satisfyFor smooth shearing-periodic extensions, spatial derivatives and products inherit the same shearing-periodic boundary condition. Their divergence therefore has zero volume average, and integration by parts is available without a residual boundary flux. Time differentiation of an average over this fixed physical box commutes with integration, even though the radial identification shifts with time.
Shearing box 2026-10-14
A shearing box solves the shearing sheet equations in a finite domain with periodic azimuthal and vertical faces and a shearing-periodic boundary condition on its radial faces. It follows a small region rotating at a reference orbital frequency. The model can sustain stress and exchange energy with its imposed differential rotation, but its identified radial faces do not represent a global disk mass sink.
Volume averages in a shearing box 2026-10-14
Periodic azimuthal and vertical boundary terms vanish. Radial boundary terms cancel after the azimuthal translation prescribed by the shearing-periodic boundary condition. Consequently the volume average of a divergence is zero, enabling integration by parts for the smooth shearing-periodic fields.